TypeError: cannot unpack non-iterable int objec

Typeerror: Cannot Unpack Non-Iterable Int Objec

We Are Going To Discuss About KindError: cannot unpack non-iterable int objec. So lets Start this Python Article.

KindError: cannot unpack non-iterable int objec

How to resolve KindError: cannot unpack non-iterable int objec

Just exchange return 0 by return 0, 0, or higher: increase an error as a substitute of returning 0
When your if situation is True, you solely return . Then later, if you do agg, gps = get_grps(...), you inform python to unpack the results of the operate. Then, python is anticipating a 2-length iterable, and attempt to unpack it, however because it says: it ‘cannot unpack non-iterable int object’…
So a fast workaround is to return a tuple (0, 0) with return 0, 0, however it’s fairly dangerous since you return integers the place objects are anticipated. your script will crash on the following line period = np.nanmean(agg['sum']) (since agg is 0).
Some cleaner options to deal with this case can be to unpack in a second time:
def get_grps(s, thresh=-1, Nmin=3): # ... if gps.isnull().all(): return None else: # ... return agg, gps for i in vary(len(data_spi)-70): ts = data_spi[i:i+10, x, y].fillna(1) consequence = get_grps(pd.Series(ts), thresh=-1, Nmin=3) if result's None: break agg, gps = consequence period = np.nanmean(agg['sum']) frequency = len(agg['sum'])

KindError: cannot unpack non-iterable int objec

Just exchange return 0 by return 0, 0, or higher: increase an error as a substitute of returning 0
When your if situation is True, you solely return . Then later, if you do agg, gps = get_grps(...), you inform python to unpack the results of the operate. Then, python is anticipating a 2-length iterable, and attempt to unpack it, however because it says: it ‘cannot unpack non-iterable int object’…
So a fast workaround is to return a tuple (0, 0) with return 0, 0, however it’s fairly dangerous since you return integers the place objects are anticipated. your script will crash on the following line period = np.nanmean(agg['sum']) (since agg is 0).
Some cleaner options to deal with this case can be to unpack in a second time:
def get_grps(s, thresh=-1, Nmin=3): # ... if gps.isnull().all(): return None else: # ... return agg, gps for i in vary(len(data_spi)-70): ts = data_spi[i:i+10, x, y].fillna(1) consequence = get_grps(pd.Series(ts), thresh=-1, Nmin=3) if result's None: break agg, gps = consequence period = np.nanmean(agg['sum']) frequency = len(agg['sum'])

Solution 1

Just exchange return 0 by return 0, 0, or higher: increase an error as a substitute of returning 0

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When your if situation is True, you solely return . Then later, if you do agg, gps = get_grps(...), you inform python to unpack the results of the operate. Then, python is anticipating a 2-length iterable, and attempt to unpack it, however because it says: it ‘cannot unpack non-iterable int object’…

So a fast workaround is to return a tuple (0, 0) with return 0, 0, however it’s fairly dangerous since you return integers the place objects are anticipated. your script will crash on the following line period = np.nanmean(agg['sum']) (since agg is 0).

Some cleaner options to deal with this case can be to unpack in a second time:

def get_grps(s, thresh=-1, Nmin=3):
    # ...
    if gps.isnull().all():
        return None
    else:
        # ...
        return agg, gps

for i in vary(len(data_spi)-70):
    ts = data_spi[i:i+10, x, y].fillna(1)

    consequence = get_grps(pd.Series(ts), thresh=-1, Nmin=3)
    if result's None:
        break

    agg, gps = consequence

    period = np.nanmean(agg['sum'])
    frequency = len(agg['sum'])

Original Author olinox14 Of This Content

Solution 2

Similar error has appeared, so to resolve this I’m posting one eg. hoping it should assist out.

Reason: since int doesn’t have __itr__ technique inside it, we will’t iterate it over like we do in checklist or tuple or dict{}.

x,y,z,n = enter() # NOT CONVERTING THE INPUT TO 'INT' HERE  

l = []  

for a in vary(0,int(x)): # changing the enter to INT  
    for b in vary(0,int(y)): # changing the enter to INT  
        for c in vary(0,int(z)): # changing the enter to INT  
            if a+b+c!= n:  
                l.append([a,b,c])  
print(l)

Original Author TUSHAR SINHA Of This Content

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Solution 3

(DJANGO)
In my case, I used to be making an attempt get a merchandise with out set which parameter for search:

 education = Schooling.objects.get(randint(1, 10)) #Error


 education = Schooling.objects.get(id=randint(1, 10)) #OK set id=

Original Author Diego Venâncio Of This Content

Conclusion

So This is all About This Tutorial. Hope This Tutorial Helped You. Thank You.

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